[402] Remove K Digits
https://leetcode.com/problems/remove-k-digits/description/
- algorithms
- Medium (25.61%)
- Source Code: 402.remove-k-digits.py
- Total Accepted: 57K
- Total Submissions: 216.1K
- Testcase Example: '"1432219"\n3'
Given a non-negative integer num represented as a string, remove k digits from the number so that the new number is the smallest possible.
Note:
The length of num is less than 10002 and will be ≥ k. The given num does not contain any leading zero.
Example 1:
Input: num = "1432219", k = 3 Output: "1219" Explanation: Remove the three digits 4, 3, and 2 to form the new number 1219 which is the smallest.
Example 2:
Input: num = "10200", k = 1 Output: "200" Explanation: Remove the leading 1 and the number is 200. Note that the output must not contain leading zeroes.
Example 3:
Input: num = "10", k = 2 Output: "0" Explanation: Remove all the digits from the number and it is left with nothing which is 0.
# coding: utf-8
class Solution(object):
def removeKdigits(self, num, k):
"""
:type num: str
:type k: int
:rtype: str
"""
lenc = len(num)
if not num or lenc <= k: return '0'
stack = []
for i in range(lenc):
if not stack:
stack.append(num[i])
else:
# print('stack, len, need, last, current', stack, len(stack)+lenc-(i+1), lenc-k, stack[-1], num[i])
while stack and len(stack) + lenc - (i+1) >= lenc - k and int(stack[-1]) > int(num[i]):
stack.pop(-1)
stack.append(num[i])
return ''.join(stack[0:lenc-k]).lstrip('0') or '0'
# s = Solution()
# print s.removeKdigits('1432219', 3)
# print s.removeKdigits('112', 1)